史上最难的三个趣味数学题！(脑子灵光的请进！)

Vongchong

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原帖由 <I>kangson</I> 于 12.9.2007 14:46 发表 <A href="http://www.kaiyuan.de/forum/redirect.php?goto=findpost&amp;pid=1434974&amp;ptid=197968" target=_blank><IMG onmousewheel="return imgzoom(this);" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor='hand'; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onclick="if(!this.resized) {return true;} else {window.open(this.src);}" alt="" src="http://www.kaiyuan.de/forum/images/common/back.gif" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" border=0></A> 在公开程序之前，再随机出3道题 &nbsp; 题目1: 2 5 8 10 用这四个数字,加减乘除都可以,组成一个等式,结果要算出24 (只能用加减乘除噢!!不能用平方等等算法.....) &nbsp; 题目2: 2 4 5 7 用这四个数字 ...

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<P>好题啊！！！</P>
<P>我放到前面的题目中去！</P>

kangson

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原帖由 <I>vanhch</I> 于 12.9.2007 14:41 发表 <A href="http://www.kaiyuan.de/forum/redirect.php?goto=findpost&amp;pid=1434965&amp;ptid=197968" target=_blank><IMG onmousewheel="return imgzoom(this);" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor='hand'; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onclick="if(!this.resized) {return true;} else {window.open(this.src);}" alt="" src="http://www.kaiyuan.de/forum/images/common/back.gif" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" border=0></A> 你去文学板块发个东西，我给你奖励。

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<P>咱老kang粗人一个，打打杀杀得还凑合，舞文弄墨就不行了</P>

Vongchong

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原帖由 <I>kangson</I> 于 12.9.2007 14:48 发表 <A href="http://www.kaiyuan.de/forum/redirect.php?goto=findpost&amp;pid=1434980&amp;ptid=197968" target=_blank><IMG onmousewheel="return imgzoom(this);" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor='hand'; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onclick="if(!this.resized) {return true;} else {window.open(this.src);}" alt="" src="http://www.kaiyuan.de/forum/images/common/back.gif" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" border=0></A> 咱老kang粗人一个，打打杀杀得还凑合，舞文弄墨就不行了

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<P>牛人啊！速度真快啊！</P>

kangson

先去工作了，下班的时候共享程序

Vongchong

没人来应答第二题了啊？

kaiser0301

原帖由 <i>Vongchong</i> 于 12.9.2007 13:34 发表 <a href="http://www.kaiyuan.de/forum/redirect.php?goto=findpost&amp;pid=1434763&amp;ptid=197968" target="_blank"><img src="http://www.kaiyuan.de/forum/images/common/back.gif" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor='hand'; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onclick="if(!this.resized) {return true;} else {window.open(this.src);}" onmousewheel="return imgzoom(this);" alt="" border="0"></a>
题目一:这是一个不成立的等式,动其中的一根,让等式成立!(别写什么1++1噢?)呵呵,上学时有这样的题目吗?所以,认真想,不是那么容易的!题目二:&nbsp;
题目2-1） 2&nbsp; 4&nbsp; 10&nbsp;&nbsp; 10&nbsp; 用这四个 ...

<br><br>解2-2: 2,5,8,10<br>LZ是不是故意把大家的思路引到特别复杂的歧途上了:<br>&nbsp;&nbsp;&nbsp; (10-5-2)*8 = 3*8 = 24<br><br>

山民甲

有答案吗？

kaiser0301

原帖由 <i>Vongchong</i> 于 12.9.2007 13:34 发表 <a href="http://www.kaiyuan.de/forum/redirect.php?goto=findpost&amp;pid=1434763&amp;ptid=197968" target="_blank"><img src="http://www.kaiyuan.de/forum/images/common/back.gif" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor='hand'; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onclick="if(!this.resized) {return true;} else {window.open(this.src);}" onmousewheel="return imgzoom(this);" alt="" border="0"></a>
题目一:这是一个不成立的等式,动其中的一根,让等式成立!(别写什么1++1噢?)呵呵,上学时有这样的题目吗?所以,认真想,不是那么容易的!题目二:&nbsp;
题目2-1） 2&nbsp; 4&nbsp; 10&nbsp;&nbsp; 10&nbsp; 用这四个 ...

<br><br>解2.3:&nbsp; 2,4,5,7<br>(4-2)*(5+7)=2*12=24<br><br>这是史上最难的数学题？<br><br>也凑个热闹，出一道题:&nbsp; 1,4,5,6, <font style="line-height: 1.3em;" _extended="true" color="#ff0099" face="黑体" size="3">用这四个数字,加减乘除都可以,组成一个等式,结果要算出24<br><br></font><br><br>

AlterWerther

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原帖由 <I>kaiser0301</I> 于 12.9.2007 20:17 发表 <A href="http://www.kaiyuan.de/forum/redirect.php?goto=findpost&amp;pid=1435389&amp;ptid=197968" target=_blank><IMG onmousewheel="return imgzoom(this);" onmouseover="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.style.cursor='hand'; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" onclick="if(!this.resized) {return true;} else {window.open(this.src);}" alt="" src="http://www.kaiyuan.de/forum/images/common/back.gif" onload="if(this.width>screen.width*0.7) {this.resized=true; this.width=screen.width*0.7; this.alt='Click here to open new window\nCTRL+Mouse wheel to zoom in/out';}" border=0></A> 解2.3:&nbsp; 2,4,5,7(4-2)*(5+7)=2*12=24这是史上最难的数学题？也凑个热闹，出一道题:&nbsp; 1,4,5,6, 用这四个数字,加减乘除都可以,组成一个等式,结果要算出24

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<P>23和25成么？</P>

AlterWerther

24找到一个犯规的。。
5^(6-4)-1